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Rankine-Hugoniot equation

The Rankine-Hugoniot equation governs the behaviour of shock waves. It is named after physicists William John Macquorn Rankine and Pierre Henri Hugoniot , French engineer, 1851-1887.

The idea is to consider one-dimensional, steady flow of a fluid subject to the Euler equations and require that mass, momentum, and energy are conserved. This gives three equations from which the two speeds, u1 and u2, are eliminated.

It is usual to denote upstream conditions with subscript 1 and downstream conditions with subscript 2. Here, ρ is density, u speed, p pressure. The symbol e means internal energy per unit mass; thus if ideal gases are considered, the equation of state is p = ρ(γ - 1)e.

The following equations

ρ1u1 = ρ2u2
p_1+\rho_1u_1^2=p_2+\rho_2u_2^2
u_1\left(p_1+\rho_1e_1+\rho_1u_1^2/2\right)= u_2\left(p_2+\rho_2e_2+\rho_2u_2^2/2\right)

are equivalent to the conservation of mass, momentum, and energy respectively. Note the three components to the energy flux: mechanical work, internal energy, and kinetic energy. Sometimes, these three conditions are referred to as the Rankine-Hugoniot conditions.

Eliminating the speeds gives the following relationship:

2\left(h_2-h_1\right)=\left(p_2-p_1\right)\cdot \left(\frac{1}{\rho_1}+\frac{1}{\rho_2}\right)

where h=\frac{p}{\rho} + e. Now if the ideal gas equation of state is used we get

\frac{p_1}{p_2}= \frac{(\gamma+1)-(\gamma-1)\frac{\rho_1}{\rho_2}} {(\gamma+1)\frac{\rho_1}{\rho_2}-(\gamma-1)}

Thus, because the pressures are both positive, the density ratio is never greater than (γ + 1) / (γ - 1), or about 6 for air (in which γ is about 1.4). As the strength of the shock increases, the downstream gas becomes hotter and hotter, but the density ratio approaches a finite limit.

Last updated: 05-17-2005 12:50:00